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Lewis Dot Diagrams
 

  1. Write the symbol for the element you are going to be writing the electron configuration. Let the symbol represent the nucleus of the atom and all of the electrons, except those in the outer energy level.


  2. Write the electron configuration for the element. Determine how many electrons are in the outer energy level. (The outer energy level is determined by the highest number before the letters (subshell)). When writing dot diagrams we are only concerned with the electrons in the outermost s and p subshells since d and f subshell electrons are always inside the outermost s and p subshells.


  3. Pretend there is an imaginary box around the symbol, leaving you with four sides on which to represent electrons (top, right, left, and bottom). You will use dots to represent the electrons in the outer energy level.


  4. There are two rules to remember: (1) s-orbital electrons are always shown as paired, and should be drawn on the same side of the symbol. (For convenience, use the top as the location for my s-orbital electrons and the sides and bottom as my p-orbital electrons. Fill in the p-orbital electron dots in a clockwise manner.) (2) Electrons will fill an empty orbital before they will pair with other electrons (Hund's Rule). Thus, you should fill each p orbital with one electron until you get to your forth p-orbital electron and then the electrons will pair up. See the diagram below.

Examples:

Lithium: 1s2 2s1 -- 2 is the outer energy level. Since it is 2s1, there is only 1 electron in the outer energy level. Thus the Lewis Dot Diagram should look like:

Beryllium: 1s2 2s2 -- 2 is the outer energy level. Since it is 2s2, there are 2 electrons in the outer energy level. Remember, both of these electrons in the outer energy level are in the s-orbital. Thus they should be written together and the Lewis Dot Diagram should look like:

Boron: 1s2 2s2 2p1 -- 2 is the outer energy level. Since it is 2s2 and 2p1, there are 3 electrons in the outer energy level. Remember, both of the electrons in the s-orbital have to be written together. The 1 p-orbital electron can go in any empty space. The Lewis Dot Diagram should look like:

Carbon: 1s2 2s2 2p2 -- 2 is the outer energy level. Since it is 2s2 and 2p2, there are 4 electrons in the outer energy level. Remember, both of the electrons in the s-orbital have to be written together. The 2 p-orbital electrons will each fill an empty space before they pair up. The Lewis Dot Diagram should look like:

Nitrogen: 1s2 2s2 2p3 -- -- 2 is the outer energy level. Since it is 2s2 and 2p3, there are 5 electrons in the outer energy level. Remember, both of the electrons in the s-orbital have to be written together. The 3 p-orbital electrons will each fill an empty space before they pair up. The Lewis Dot Diagram should look like:

Oxygen: 1s2 2s2 2p4 -- 2 is the outer energy level. Since it is 2s2 and 2p4, there are 6 electrons in the outer energy level. Remember, both of the electrons in the s-orbital have to be written together. The 4 p-orbital electrons will each fill an empty space before they pair up. Since there are only 3 empty spaces but 4 p electrons, two of the electrons must double up. The Lewis Dot Diagram should look like:

Fluorine: 1s2 2s2 2p5 -- 2 is the outer energy level. Since it is 2s2 and 2p5, there are 7 electrons in the outer energy level. Remember, both of the electrons in the s-orbital have to be written together. The 5 p-orbital electrons will each fill an empty space before they pair up. Since there are only 3 empty spaces but 5 p electrons, four of the electrons must double up. The Lewis Dot Diagram should look like:

Neon: 1s2 2s2 2p6 -- 2 is the outer energy level. Since it is 2s2 and 2p6, there are 8 electrons in the outer energy level. Remember, both of the electrons in the s-orbital have to be written together. The 6 p-orbital electrons will each fill an empty space before they pair up. Since there are only 3 empty spaces but 6 p electrons, all six of the electrons must double up. The Lewis Dot Diagram should look like:


In summary, elements in:
group 1 (IA) will have one dot in the s orbital.
group 2 (IIA) will have 2 dots, both in the s orbital.
group 13 (IIIA) will have 3 dots, 2 in the s orbital and 1 in the first p orbital.
group 14 (IVA) will have 4 dots, 2 in the s orbital, 1 in the first p orbital and 1 in the second p orbital.
group 15 (VA) will have 5 dots, 2 in the s orbital, 1 in the first p orbital, 1 in the second p orbital and 1 in the third p orbital.
group 16 (VIA) will have 6 dots, 2 in the s orbital, 2 in the first p orbital, 1 in the second p orbital and 1 in the third p orbital.
group 17 (VIIA) will have 7 dots, 2 in the s orbital, 2 in the first p orbital, 2 in the second p orbital and 1 in the third p orbital.
group 18 (VIIIA) will have 8 dots, 2 in the s orbital, 2 in the first p orbital, 2 in the second p orbital and 2 in the third p orbital.


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